From edge length
For a = 6 cm, h = 6√(2/3) ≈ 4.8990 cm, S = 36√3 ≈ 62.3538 cm², and V = 216/(6√2) ≈ 25.4558 cm³.
Enter one value. You may enter more to check whether rounded measurements describe the same regular tetrahedron.
Let a be the common edge length. These formulas use ordinary Euclidean geometry.
| Measurement | Formula from edge a | Edge from measurement |
|---|---|---|
Height h | h = a√(2/3) | a = h√(3/2) |
One-face area A | A = √3a²/4 | a = √(4A/√3) |
Total surface area S | S = √3a² | a = √(S/√3) |
Volume V | V = a³/(6√2) | a = ∛(6√2V) |
Inradius r | r = a√6/12 | — |
Circumradius R | R = a√6/4 | — |
The surface area is exactly four times one-face area. The center divides the height in a 3:1 ratio, so R = 3r and h = R + r.
Formula check: results use S = √3a², V = a³/(6√2) and h = a√(2/3), plus their algebraic rearrangements.
Length units become squared for area and cubed for volume. Conversions occur before calculations, and rounding is applied only to displayed results. Very small and very large results use scientific notation.
Calculations run locally in your browser. Last reviewed: July 30, 2026.
For a = 6 cm, h = 6√(2/3) ≈ 4.8990 cm, S = 36√3 ≈ 62.3538 cm², and V = 216/(6√2) ≈ 25.4558 cm³.
For S = 100 cm², a = √(100/√3) ≈ 7.5984 cm. The height is approximately 6.2040 cm.
For V = 1000 mm³, a = ∛(6000√2) ≈ 20.3965 mm. The total surface area is approximately 720.5622 mm².
It solves a regular tetrahedron: a solid made from four congruent equilateral-triangle faces, with all six edges equal.
For edge length a, volume is V = a³/(6√2), equivalent to √2a³/12.
The total surface area is S = √3a². Each of the four equilateral faces has area √3a²/4.
The perpendicular height from a vertex to the opposite face is h = a√(2/3).
Yes. Rearranging the volume formula gives a = ∛(6√2V).
The inradius runs from the center to a face and equals a√6/12. The circumradius runs from the center to a vertex and equals a√6/4, three times the inradius.
Yes. Each input has its own unit. If you enter more than one value, the calculator converts them to a common scale and checks whether they describe the same tetrahedron.
No. The calculation runs locally in your browser, and the tool does not send or store your measurements.