Absolutely convergent
Both the improper integral and the integral of |f(x)| converge. This is stronger than ordinary convergence.
Test whether an integral with infinite bounds or isolated singularities converges. The calculator splits every required one-sided limit, looks for a verified antiderivative, checks absolute convergence, and shows finite-cutoff evidence when a symbolic conclusion is unavailable. Calculations stay in your browser.
| Required part | Conclusion | Contribution | Method |
|---|---|---|---|
| One-sided parts will appear here. | |||
Analyze an integral to compare successively more extreme cutoffs. A flattening trace is evidence, not a general proof.
inf or -inf for an infinite bound. For a finite discontinuity, list the point even if it is also an endpoint.Both the improper integral and the integral of |f(x)| converge. This is stronger than ordinary convergence.
The signed integral converges, but the absolute-value integral diverges. Cancellation is essential.
At least one required one-sided antiderivative limit is non-finite or fails to exist. One bad part makes the whole improper integral diverge.
The available exact rules and finite cutoff sequence do not justify a confident classification. A comparison, limit comparison, or another analytic test may be needed.
| Form | Definition or convergence rule |
|---|---|
| Infinite upper bound | ∫ₐ∞ f(x)dx = lim R→∞ ∫ₐᴿ f(x)dx |
| Singular lower endpoint | ∫ₐᵇ f(x)dx = lim ε→0⁺ ∫ₐ₊εᵇ f(x)dx |
| Tail p-integral | ∫₁∞ 1/xᵖ dx converges exactly when p > 1. |
| Endpoint p-integral | ∫₀¹ 1/xᵖ dx converges exactly when p < 1. |
It converges only when every limit introduced by an infinite bound or singular point exists as a finite real number. If the interval is split, every piece must converge.
An improper integral converges absolutely when the corresponding integral of |f(x)| converges. Absolute convergence guarantees ordinary convergence; the converse need not hold.
No. Symmetric cancellation can produce a finite principal value even when the left- and right-hand improper integrals diverge. This calculator tests the sides independently.
Finite numerical samples cannot settle every limit, especially slowly converging tails and highly oscillatory functions. The calculator reports uncertainty instead of turning a cutoff estimate into a false proof.
Yes. The calculator performs a limited scan, but it cannot prove that it found every discontinuity. Enter all known isolated singularities so each one-sided integral is tested.
This tool is specifically for improper integrals. Use the Integral Calculator when both bounds are finite and the integrand is continuous throughout.
No. Parsing, integration, limit checks, graphing, copying, permalink construction and CSV generation happen locally.