Formulas and decision rules
Absolute value is distance from zero. Its piecewise definition is:
Direct equation roots
For a โ 0 and c > 0:
Center and radius
For |ax+b| < c, the solution lies within radius c/|a| of center โb/a. Greater-than relations select the outside rays.
Inside: AND
Outside: OR
Threshold decision table
| Relation | c < 0 | c = 0 | c > 0 |
|---|---|---|---|
| = | No solution | One root: u = 0 | Two cases: u = ยฑc |
| < | No solution | No solution | โc < u < c (AND) |
| โค | No solution | u = 0 | โc โค u โค c (AND) |
| > | All real x | u โ 0 | u < โc or u > c (OR) |
| โฅ | All real x | All real x | u โค โc or u โฅ c (OR) |
Method reference: OpenStax College Algebra 2e, ยง2.7 explains interval notation, inequality reversal, and absolute-value inequalities.
Worked examples for every case
=: two exact roots โ |2xโ3|=5
- Split:
2xโ3=โ5or2xโ3=5. - Add 3:
2x=โ2or2x=8. - Divide by 2:
x=โ1orx=4. - Check: both substitutions give absolute value 5.
<: inside, open endpoints โ |3x+1|<7
โ7<3x+1<7.- Subtract 1:
โ8<3x<6. - Divide by 3:
โ8/3<x<2. - Interval:
(โ8/3,2).
โค: inside, closed endpoints โ |xโ4|โค2
โ2โคxโ4โค2.- Add 4:
2โคxโค6. - Interval:
[2,6]; both boundaries are included.
>: outside, open endpoints โ |x+2|>3
x+2<โ3orx+2>3.- Subtract 2:
x<โ5orx>1. - Interval:
(โโ,โ5) โช (1,โ).
โฅ and negative a โ |โ2x+4|โฅ6
โ2x+4โคโ6orโ2x+4โฅ6.โ2xโคโ10orโ2xโฅ2.- Divide by โ2 and reverse both signs:
xโฅ5orxโคโ1.
Fractional coefficient โ |(3/4)xโ1|=5/2
(3/4)xโ1=โ5/2or(3/4)xโ1=5/2.(3/4)x=โ3/2or(3/4)x=7/2.- Multiply by 4/3:
x=โ2orx=14/3.
One solution and zero threshold โ |xโ3|=0
- An absolute value is zero only when its interior is zero.
xโ3=0, sox=3.
No solution โ |x|=โ2
|x|โฅ0for every real x.- It cannot equal โ2, so the solution set is
โ.
All real numbers โ |x|โฅ0
- Absolute value is nonnegative by definition.
- The statement is true for every real x:
(โโ,โ).
Constant expression (a=0) โ |0x+3|โฅ2
|0x+3|=3for every x.3โฅ2is true, so every real number works.
Common mistakes and quick corrections
Forgetting the negative case
|x|=4 gives x=4 and x=โ4.
Using OR for an inside interval
|x|<3 means โ3<x<3 (AND), not two outside rays.
Not reversing a sign
โ2x>6 becomes x<โ3 after division by โ2.
Including strict endpoints
|x|<2 uses open endpoints: (โ2,2).
Ignoring a negative threshold
|x|<โ1 has no solution because |x|โฅ0.
Mixing brackets and parentheses
xโฅ2 is [2,โ): include 2 with a bracket, never bracket infinity.
Distance and tolerance applications
Comfortable temperature
Within 4ยฐF of 72ยฐF is |Tโ72|โค4, so 68โคTโค76.
Manufacturing tolerance
A part within 0.5 mm of 10 mm is |xโ10|<0.5, so 9.5<x<10.5.
Distance from a landmark
At least 3 km from position 8 is |xโ8|โฅ3, so xโค5 or xโฅ11.
Methodology, verification, privacy, and limits
Authorship: Starlight Tools. No independent credentialed mathematics reviewer is currently listed. The transparent calculation methodology follows the absolute-value and inequality rules cited above. Last methodology review: 31 August 2026.
Test evidence: the pageโs automated self-checks cover two-root, one-root, no-solution, all-real-number, all five relations, negative outer and inner coefficients, fractional coefficients, zero and negative thresholds, constant expressions, and a right-side absolute-value group. A failed self-check is reported in the browser console rather than hidden.
Numbers are converted to reduced fractions and processed with BigInt arithmetic. Each numeric part is limited to 30 digits. Scientific and repeating-decimal notation are unsupported; use an exact fraction. Multiple absolute-value groups, nonlinear interiors, and variables outside the absolute-value group are outside this calculatorโs one-group linear scope.
All solving happens locally in your browser. The calculator does not transmit or store your equation or inequality.
Absolute value solver FAQs
How do you solve an absolute value equation?
For positive c, split |u| = c into u = -c or u = c, then solve both linear equations. A zero threshold gives one case, and a negative threshold gives no real solution.
How do you solve an absolute value inequality?
For positive c, less-than relations become one compound inequality between -c and c joined by AND. Greater-than relations become two outside inequalities joined by OR. Inclusive symbols include the endpoints.
Why can an absolute value problem have no solution?
An absolute value cannot be negative. A constant absolute-value expression can also make the comparison false for every real x.
Can the solution be all real numbers?
Yes. For example, |x| โฅ 0 is always true. If a = 0, the expression is constant and the original comparison is either true for every real x or false for all of them.
Can I enter fractions and decimals?
Yes. Use integers, finite decimals, or fractions such as -3/4. Exact fractions are reduced automatically.
Is this absolute value solver private?
Yes. It solves locally in your browser and does not send or store the values you enter.