1. Use effective width
Measure the strip actually covered. Subtract intentional overlap from nominal implement width unless that same loss is already represented in field efficiency.
Estimate how many acres or hectares a tractor and implement can cover, how long the operation will take, and the resulting fuel use and cost.
Changing unit systems converts the entered area, width, speed, fuel rate, and fuel price.
Currency changes formatting only; enter the fuel price in the selected currency.
Use the width actually covered, not necessarily the machine’s nominal width.
Accounts for turns, overlap, filling, adjustments, and other field delays.
Use 2 for two complete operations over the same field.
Prefer a measured or operation-specific average over rated maximum consumption.
Used for the completion check and required-width estimate.
Enter a field operation to calculate capacity, time, fuel, and cost.
| Operation measure | Result |
|---|---|
| Calculate to see the operation summary. | |
Effective capacity adjusts theoretical coverage by the entered field efficiency.
Measure the strip actually covered. Subtract intentional overlap from nominal implement width unless that same loss is already represented in field efficiency.
An average from tractor records, a fuel-flow display, or actual refilling is usually more useful than maximum rated fuel consumption.
Field shape, row length, terrain, operator practice, filling, unloading, and machine type can materially change effective capacity.
U.S. theoretical capacity (acres/hour) = width (ft) × speed (mph) ÷ 8.25
Metric theoretical capacity (ha/hour) = width (m) × speed (km/h) ÷ 10
Effective capacity = theoretical capacity × field efficiency ÷ 100
Total time = field area × passes ÷ effective capacity
Total fuel = total time × average fuel use per hour
Total fuel cost = total fuel × fuel price
Required width = target capacity × conversion factor ÷ (speed × field efficiency as a decimal)
The 8.25 factor is the standard rounded conversion from square feet per hour to acres per hour; 10 is the corresponding metric factor. The calculator assumes constant effective width, average speed, field efficiency, and hourly fuel rate across all passes. It treats entered passes as complete repetitions over the original field and excludes labor, repairs, depreciation, finance, lubricants, transport to the field, and implement ownership costs.
A 30-foot implement moving at 5.5 mph has a theoretical capacity of 20 acres per hour. At 80% field efficiency, effective capacity is 16 acres per hour. One pass over 160 acres takes 10 operating hours.
At an average 8.5 US gallons per hour, the job uses 85 gallons. With fuel at $3.75 per gallon, total fuel cost is $318.75, or about $1.99 per acre. At 10 operating hours per day, the operation fits within one workday; the two-day target would require an effective working width of about 15 feet under the same assumptions.
The references support the capacity and cost-allocation method, not the default inputs. Use field records, equipment documentation, and current local fuel prices for an operation-specific estimate.
In U.S. units, multiply effective working width in feet by speed in mph, divide by 8.25, then multiply by field efficiency as a decimal. In metric units, multiply width in metres by speed in km/h, divide by 10, then apply field efficiency.
It represents the gap between ideal continuous coverage and actual capacity. Turning, overlap, filling, unloading, checks, adjustments, short stops, and irregular field shape can all reduce efficiency.
The calculator multiplies total field time by average hourly fuel use and fuel price, then divides by the original field area. Because the denominator is the original field area, the per-area result includes all entered passes.
Use effective working width. If intentional overlap narrows the actual strip, enter that narrower width. Avoid representing the same overlap in both working width and field efficiency.
Use an average rate representative of the complete field operation. If the only available figure is full-load fuel consumption, treat the result cautiously because normal field load may differ.
Every complete pass repeats work across the field. With other inputs held constant, two passes require twice the machine time, fuel, and fuel cost of one pass.
No. Calculations run entirely in the browser, and this tool does not send or store entered values.
This calculator is a planning and budgeting aid, not operating, machinery-selection, financial, or safety advice. Actual speed, efficiency, fuel consumption, usable work hours, soil conditions, slope, traction, weather, and safe implement width can differ materially. Follow equipment ratings and operator manuals, never exceed safe field speed or tractor/implement limits, and validate important budgets with field records or a qualified machinery adviser.