Beam Load Calculator (Simply Supported)
Enter the beam length, add point loads and UDLs, and we’ll compute support reactions plus draw the shear force and bending moment diagrams. Private, in-browser.
Inputs
Point Loads (downward +)
Load P (kN) | Position x (m) | Actions |
---|
Uniformly Distributed Loads (UDL)
Intensity w (kN/m) | Start a (m) | End b (m) | Actions |
---|
Results
What This Calculator Does
We assume a simply supported beam (pin at the left end, roller at the right). You can add point loads and uniformly distributed loads (UDLs). Reactions are found by static equilibrium: ∑F = 0 and ∑MA = 0. The shear function V(x) is evaluated piecewise across all load breakpoints; the bending moment is computed via numerical integration of V(x).
FAQs
Can I add moments or overhangs?
Not yet. This v1 focuses on the most common case: simply supported with point loads and UDLs. If you need concentrated moments or cantilevers, we may add those in a future version.
Why is a reaction negative?
That indicates uplift would be required at that support under the given loading, which a simple pin/roller cannot provide. Re-check inputs or support conditions.
How accurate are the diagrams?
They’re high-fidelity for statics. We sample densely between every breakpoint so the SFD/BMD capture the correct linear/parabolic behavior for UDLs and point loads.
Shear Force & Bending Moment — Concepts, Examples, and Tips
This tool helps you sketch the shear force diagram (SFD) and bending moment diagram (BMD) for a simply supported prismatic beam (pin at the left, roller at the right). It supports point loads and uniformly distributed loads (UDLs), computes support reactions, and draws SFD/BMD live. All calculations run privately in your browser.
When to Use This
- Quick checks during early sizing or coursework.
- Understanding how loads change shear/moment shape before a detailed design package.
- Exploring “what if” scenarios (moving a point load, adjusting a UDL length, etc.).
Inputs & Units
- Beam length \(L\): metres (m)
- Point load \(P\): kilonewtons (kN), downward taken as positive here
- UDL \(w\): kilonewtons per metre (kN/m)
- Shear \(V\): kN | Moment \(M\): kN·m
How the Calculations Work
Reactions are found from static equilibrium with the origin at the left support:
\( R_B = \dfrac{\displaystyle \sum_i P_i x_i + \sum_j w_j\,(b_j - a_j)\,\dfrac{a_j + b_j}{2}}{L}, \qquad R_A = \sum_i P_i + \sum_j w_j\,(b_j - a_j) - R_B. \)
The shear function at a position \(x\) (0 at the left support) is:
\( V(x) = R_A - \sum_{x_i \le x} P_i - \sum_j w_j\,\max\!\bigl(0,\,\min(x,b_j)-a_j\bigr). \)
Moment follows from \( \dfrac{dM}{dx} = V \). We integrate shear numerically from 0 to \(x\):
\( M(x) = \int_0^x V(s)\,ds \) (we choose \(M(0)=0\)).
Worked Example (Step-by-Step)
Beam: \(L = 6\,\text{m}\). Point load \(P_1 = 10\,\text{kN}\) at \(x=2\,\text{m}\). UDL \(w = 3\,\text{kN/m}\) from \(a=3\,\text{m}\) to \(b=6\,\text{m}\).
- Total load: \( \sum P = 10 + 3(6-3) = 19\,\text{kN}. \)
- Moment about left support: \( \sum M_A = 10\cdot2 + 3(3)\cdot\dfrac{3+6}{2} = 20 + 9\cdot4.5 = 60.5\,\text{kN·m}. \)
- Reactions: \( R_B = 60.5/6 = 10.083\,\text{kN}, \quad R_A = 19 - 10.083 = 8.917\,\text{kN}. \)
- Shear just right of loads:
- For \(0\le x<2\): \(V = 8.917\) (horizontal line)
- At \(x=2\): jump down by \(10\) → \(V = -1.083\)
- For \(3\le x\le 6\): UDL reduces shear linearly with slope \(-w=-3\) kN/m
- Moment: area under the shear curve. The BMD rises to a maximum near where \(V(x)=0\).
Tip: In a simply supported beam without applied end moments, the global maximum sagging moment occurs where \(V(x)=0\).
Interpreting the Diagrams
- Point load → shear diagram has a jump; moment diagram has a change in slope.
- UDL → shear diagram is linear; moment diagram is quadratic (parabolic).
- Zero-shear location (\(V=0\)) marks a local extremum of the bending moment.
Common Mistakes (and Fixes)
- Loads outside the span: Keep all point-load positions and UDL intervals within \(0 \le x \le L\).
- Sign confusion: Here, downward loads are positive; support reactions are positive upwards.
- UDL endpoints reversed: Enter start \(a\) ≤ end \(b\); the tool will warn if they’re flipped.
- Unexpected negative reactions: Indicates uplift at a support — re-check load positions or the support model.
Assumptions & Limits
- Statically determinate, simply supported beam; prismatic section.
- Linear statics only (no deflection, slope, stresses, or shear deformation effects).
- Loads are vertical; no axial forces or torsion.
- Use with judgement; for real projects, defer to a qualified structural engineer and the applicable design standards.
Glossary
- Shear force \(V\): internal transverse force at a section.
- Bending moment \(M\): internal couple at a section; \(dM/dx = V\).
- UDL: uniformly distributed load, constant \(w\) over an interval.
- Reaction: support force that balances applied loads.
Disclaimer: Educational tool. Not a substitute for professional structural analysis or code-compliant design checks.