Current and power from V and R
9 V and 1.5 kΩ (1500 Ω) give 0.006 A (6 mA) and 0.054 W (54 mW).
Enter any two values—voltage, current, resistance, or power—to calculate the other two using V=IR and P=VI.
Leave both unknown fields blank. A result appears automatically once two valid values are present.
Hints: Enter calculates · Esc clears · Values auto-scale (e.g., 0.002 A → 2 mA).
Every useful rearrangement of Ohm’s Law and Watt’s Law is shown as readable text.
| Voltage (V) | Current (I) | Resistance (R) | Power (P) |
|---|---|---|---|
V = I × R | I = V ÷ R | R = V ÷ I | P = V × I |
V = P ÷ I | I = P ÷ V | R = V² ÷ P | P = V² ÷ R |
V = √(P × R) | I = √(P ÷ R) | R = P ÷ I² | P = I² × R |
Example: enter 9 V and 1.5 kΩ; the calculator converts 1.5 kΩ to 1500 Ω and finds 6 mA and 54 mW.
Ohm’s Law relates voltage, current, and resistance as V = I × R. Joule’s power relationship is P = V × I. This calculator converts all entries to volts, amperes, ohms, and watts before applying those equations.
Applicability: this is an ideal, steady, resistive-load model—not a model of every circuit. Resistance may change with temperature. Capacitors and inductors in AC circuits require frequency-dependent impedance and phase; LEDs and other semiconductors require nonlinear device curves or datasheets.
Resistance versus impedance: resistance is the real opposition modeled here. Impedance combines resistance and reactance and may introduce a phase difference between AC voltage and current.
9 V and 1.5 kΩ (1500 Ω) give 0.006 A (6 mA) and 0.054 W (54 mW).
12 V and 6 mA (0.006 A) give 2000 Ω (2 kΩ) and 72 mW.
0.25 W and 100 Ω give √(0.25 × 100) = 5 V and 50 mA.
12 V across 1 kΩ dissipates 0.144 W. Choose a rating above the calculated dissipation with suitable design margin and verify the datasheet.
Ohm’s Law states that voltage equals current multiplied by resistance: V = IR, for an ideal ohmic resistive load under steady conditions.
Use V = IR and P = VI. Rearranging these gives V = IR, I = V/R, R = V/I, and power forms P = VI = V²/R = I²R.
Enter exactly two known values from voltage, current, resistance, and power, with their units. Leave the other two fields blank.
The simple real-number form works directly for steady DC resistive loads and purely resistive AC values. General AC circuits require impedance and phase, usually represented with complex quantities.
Resistance opposes current without a phase model. Impedance includes resistance and frequency-dependent reactance from capacitance or inductance, and can shift phase in AC circuits.
Component tolerance, temperature, source and meter resistance, wiring losses, noise, and changing or nonlinear behavior can make measured values differ from this ideal estimate.
Not as a fixed-resistance model across all operating points. LEDs and other semiconductors are nonlinear; use their datasheets or characteristic curves and apply Ohm’s Law only to appropriate circuit elements such as a series resistor.
Prepared by: Starlight Tools technical editorial team. Technical review: Starlight Robotics engineering team. Reviewed: 12 July 2026. Updated: 12 July 2026.
Method: inputs are converted to SI units, solved using standard Ohm’s Law and Joule’s Law equations, checked for a finite physical result, and converted to the chosen display units.
References: NIST: SI Units—Electric Current; All About Circuits: nonlinear conduction; All About Circuits: resistance, reactance, and impedance; OSHA electrical requirements.
Educational estimate only. It does not replace component datasheets, manufacturer ratings, applicable electrical codes, qualified design review, or electrical safety requirements.