Actual yield
Use the product amount actually isolated or measured.
Use the product amount actually isolated or measured.
This usually comes from stoichiometry and the limiting reagent.
Chemistry formula: (actual ÷ theoretical) × 100.
| Quantity | Entered / solved value | Equivalent moles | Notes |
|---|---|---|---|
| Converted values will appear here. | |||
Percent yield compares how much product you actually obtained with how much you should have obtained under ideal stoichiometric completion.
If you enter grams, milligrams, kilograms, or gas volume, the calculator needs a molar mass or a parseable chemical formula for the product. Percent yield above 100% can occur from impure product, retained solvent, weighing error, or an incorrect theoretical-yield estimate during experimental work.
Silver chloride precipitation: if the theoretical yield of AgCl is 14.34 g and you isolate 12.50 g, the percent yield is about 87.17%.
Water synthesis: if stoichiometry predicts 2.00 mol H₂O and you collect 1.84 mol, percent yield is 92.0%.
Solve for actual yield: if the theoretical yield is 10.0 g and the process gives 78%, the actual yield is 7.80 g.
Common causes include incomplete reaction, transfer losses, side reactions, filtration loss, or product left dissolved in solvent.
Usually because the collected product still contains solvent or impurities, or because the theoretical-yield estimate was too low. It is a useful warning flag, not a chemical impossibility theorem.
Yes. The calculator converts both yields to moles internally. For any mass-based entry, you need a molar mass.
No. Stoichiometry gives the theoretical yield first. This page then compares that theoretical amount with your measured product.
Actual and theoretical yield must refer to the same product species. Otherwise the ratio is chemically meaningless.
It comes from balanced-equation stoichiometry and the limiting reagent, assuming ideal conversion and collection.
Grams, moles, particles, and ideal-gas volume can all represent the same amount of the same product once converted consistently.
A large mass can still include impurities or trapped solvent, so percent yield and purity answer different questions.
You still need stoichiometry or experiment to establish the theoretical amount first. Percent yield only compares that benchmark with what you actually recovered.