From moles: 3 mol in 0.5 kg solvent
m = n / kg = 3 / 0.5 = 6 mol/kg
Leave exactly one of moles, solvent mass, or molality blank.
Formula checked: molality equals moles of solute per kilogram of solvent. Calculations run locally in your browser.
| Quantity | Formula | Meaning |
|---|---|---|
| Molality | m = n / kg solvent | Moles of solute per kilogram of solvent. |
| Solute moles | n = mass / MW | Moles from solute mass and molar mass. |
| Target solute mass | mass = m x kg solvent x MW | Mass of solute needed for a target molality. |
| Target solvent mass | kg solvent = n / m | Solvent mass required to reach a target molality. |
| Target moles | n = m x kg solvent | Solute amount needed for a known solvent mass. |
Molality uses kilograms of solvent, not liters of solution. That is why it stays useful when solution volume changes with temperature.
| Feature | Molality | Molarity |
|---|---|---|
| Definition | Moles per kilogram of solvent | Moles per litre of solution |
| Symbol | lowercase m | uppercase M |
| Unit | mol/kg | mol/L |
| Denominator | Solvent mass | Total solution volume |
| Temperature dependence | Essentially independent | Can change as volume changes |
| Common use | Colligative properties | Volumetric solution preparation |
m = n / kg = 3 / 0.5 = 6 mol/kg
n = 70.128 g / 58.44 g/mol = 1.2 mol
m = 1.2 / 1.5 = 0.8 mol/kg
With 2.5 kg solvent: n = m × kg = 0.8 × 2.5 = 2 mol.
For 1.5 mol at 0.6 mol/kg: kg solvent = n / m = 1.5 / 0.6 = 2.5 kg.
The page converts any entered solute mass to moles using the molar mass, then divides by kilograms of solvent. When you solve in reverse, it rearranges the same relationship to recover the missing solute mass, solvent mass, or moles.
Molality is often used in colligative-property work and other temperature-sensitive solution problems because the solvent mass does not depend on thermal expansion the way a solution volume does. That makes molality especially convenient for freezing-point depression, boiling-point elevation, and careful solution-composition comparisons.
These conversions require solution density and solute molar mass. Use density d in kg/L and molar mass W in kg/mol.
M = m × d / (1 + m × W); reverse: m = M / (d − M × W).
Divide moles of solute by kilograms of solvent: m = n / kg solvent.
The molality is 3 / 0.5 = 6 mol/kg.
Molality is measured in moles per kilogram of solvent, written mol/kg or mol kg^-1.
Use the mass of the solvent only, not the total mass of the solution.
Divide solute mass in grams by molar mass in g/mol to get moles, then divide those moles by solvent mass in kilograms.
Using density d in kg/L and molar mass W in kg/mol, calculate M = m × d / (1 + m × W).
This page performs concentration arithmetic only. It does not derive molar mass or density, or correct for purity, hydration state, evaporation, or non-ideal solution behavior. Verify your inputs and lab method.