Electron localized to 0.10 nm
Inputs: Δx = 0.10 nm, mass = electron.
Substitution: Δp = ħ/(2Δx).
Result: Δp ≥ 5.2729×10^-25 kg·m/s and Δv ≥ 5.7884×10^5 m/s.
Calculate minimum uncertainty in position, momentum, velocity, energy, or time using ΔxΔp ≥ ħ/2 and ΔEΔt ≥ ħ/2. Enter one value to solve the minimum paired uncertainty, or enter both to check whether the pair satisfies the bound.
| Symbol | Meaning | SI unit |
|---|---|---|
| Δx | Position uncertainty, as a standard deviation | m |
| Δp | Momentum uncertainty, as a standard deviation | kg·m/s |
| Δv | Velocity uncertainty for a massive non-relativistic particle, using Δp = mΔv | m/s |
| ΔE | Energy uncertainty or energy width | J |
| Δt | Time scale, lifetime, or pulse duration | s |
| h | Planck constant | J·s |
| ħ | Reduced Planck constant, h/(2π) | J·s |
Inputs: Δx = 0.10 nm, mass = electron.
Substitution: Δp = ħ/(2Δx).
Result: Δp ≥ 5.2729×10^-25 kg·m/s and Δv ≥ 5.7884×10^5 m/s.
Inputs: Δx = 1 fm, mass = proton.
Substitution: Δp = ħ/(2×10^-15 m).
Result: Δp ≥ 5.2729×10^-20 kg·m/s and Δv ≥ 3.1523×10^7 m/s.
Inputs: Δt = 10 fs.
Substitution: ΔE = ħ/(2Δt).
Result: ΔE ≥ 0.03291 eV.
Inputs: Δt = 1 ns lifetime.
Substitution: ΔE = ħ/(2×10^-9 s).
Result: ΔE ≥ 3.2911×10^-7 eV.
Inputs: Δx = 1 μm, mass = 0.145 kg.
Substitution: Δv = ħ/(2mΔx).
Result: Δv ≥ 3.6365×10^-28 m/s, far below everyday velocity scales.
Δx · Δp ≥ ħ/2 with ħ = h/(2π) = 1.054571817×10⁻³⁴ J·s. If you provide Δx, we compute minimum Δp = ħ/(2Δx), and vice versa.ΔE · Δt ≥ ħ/2 relates energy spread to a lifetime, pulse width, or evolution timescale. Same algebra: minimum partner = ħ/(2·known).ħ/2. A ratio ≥ 1 satisfies the bound. A ratio < 1 means the pair is impossible in simple quantum mechanics.All calculations convert inputs to SI internally. Displayed results can be converted back to the selected output units, and each Copy SI button copies the unrounded SI value.
Sources: NIST CODATA fundamental constants; Encyclopaedia Britannica on the uncertainty principle; Stanford Encyclopedia of Philosophy on uncertainty relations.
The Heisenberg uncertainty principle sets a floor on how well pairs of conjugate quantities can be specified. For position and momentum, Δx · Δp ≥ ħ/2 tells you that squeezing a particle’s position wavefunction forces its momentum spread to widen. This isn’t about clumsy measurement; it’s about how wavefunctions are built from Fourier components. A narrow pulse in space requires many momentum components, creating a broad spread in momentum space. The calculator treats Δx and Δp as standard deviations—the common textbook form. If you enter one, it returns the minimum possible value of the other, assuming a Gaussian wave packet (the minimum-uncertainty shape).
Energy–time is trickier because time isn’t an operator in non-relativistic quantum mechanics. Still, ΔE · Δt ≥ ħ/2 gives a useful rule of thumb: rapid processes (small Δt) require broad energy spreads (large ΔE). You see this in ultrafast lasers: a 10 femtosecond pulse naturally spans a wide spectrum because its coherence time is so short. In nuclear and particle physics, short-lived excited states have wide energy widths (Γ), reflecting the same relation. Our calculator uses the same algebra: given ΔE, it returns the minimum Δt, and vice versa.
Ratios help you sanity-check homework. If your Δx·Δp ratio is below 1, the numbers can’t describe a physical state in the simple Heisenberg picture—revisit your units or assumptions. If it is exactly 1, you’re at the limit. Anything above 1 is allowed; real systems often sit above the bound because their wavefunctions aren’t perfect Gaussians. The bar visualization caps at 300% to stay readable, but the numeric ratio shows the true value. The product values also carry the same units as ħ (J·s) for both pairs, since 1 J·s = 1 kg·m²/s.
Try the presets: the position example uses an atomic-scale Δx to show that even modest momentum spreads satisfy the bound. The laser-like energy–time example highlights why short pulses carry broad spectra. You can also test macroscopic masses to see why classical intuition works: even “tiny” positional uncertainties translate to negligible momentum lower bounds. If you need relativistic precision, remember that momentum becomes p = γmv; that only raises Δp for a given Δx, so it never violates the bound. Keep units consistent, and let the ratio guide whether your numbers pass the fundamental test.
The common textbook forms are ΔxΔp ≥ ħ/2 and ΔEΔt ≥ ħ/2. Here ħ is the reduced Planck constant, h/(2π).
Enter Δx and leave Δp blank. The tool converts Δx to meters and calculates Δp_min = ħ/(2Δx).
Choose a particle mass or enter a custom mass. The calculator first finds Δp, then uses Δv = Δp/m for a massive non-relativistic particle.
ħ/2 is half the reduced Planck constant. Numerically it is about 5.2729×10^-35 J·s.
You can use the dropdowns for common classroom and physics units, including nm, Å, eV, MeV, fs, and eV/c. Internally the calculator uses SI values.
If the ratio is below 1, the entered pair gives a product smaller than ħ/2. That usually means a unit conversion error or a pair that cannot represent a valid quantum state in this model.
No. The uncertainty here is the spread of a quantum state, often represented by a standard deviation. It is not simply imprecision in the measuring device.
Position and momentum are operator observables in standard quantum mechanics, while time is normally a parameter. Energy-time uncertainty is still useful for lifetimes, linewidths, and pulse bandwidths, but its interpretation is more context-dependent.