Volume of a sphere with radius 5
With r = 5 cm, d = 10 cm, A = 100π cm² ≈ 314.16 cm², and V = 500π/3 cm³ ≈ 523.60 cm³.
Results update as you type. Unit controls label the result dimensions; they do not convert between unrelated length, area, and volume inputs.
Enter two or more measurements using matching units to check whether they describe the same sphere.
This sphere calculator finds volume, surface area, radius, diameter, and great-circle circumference from one known measurement. Choose whether you know r, d, C, A, or V, enter the value, and the calculator immediately solves the remaining measurements with decimal results, exact π forms when available, and compact solution steps.
A sphere is completely defined by its radius r. Once you know the radius, the rest follows: d = 2r, C = 2πr, A = 4πr², and V = (4/3)πr³. If you start with diameter, circumference, surface area, or volume, the calculator works backward to find the radius and then calculates everything else.
How to use it:
This is helpful when a real object is easier to measure one way than another. For example, you can wrap a string around the widest part of a ball to get circumference, use a tank diameter to estimate capacity, or start from a required volume to find the radius needed for a design.
Units: radius, diameter, and circumference use length units such as cm; surface area uses square units such as cm²; volume uses cubic units such as cm³. The unit selectors label the measurements clearly, but they do not convert a surface-area input into an unrelated length unit.
Last reviewed: June 7, 2026
Author/reviewer: Starlight Tools editorial team
Method: Standard Euclidean sphere formulas using the selected π value.
Accuracy note: Calculations run client-side and are rounded only for display.
| Known value | Radius r | Diameter d | Circumference C | Surface area A | Volume V |
|---|---|---|---|---|---|
| Radius r | r |
2r |
2πr |
4πr² |
(4/3)πr³ |
| Diameter d | d/2 |
d |
πd |
πd² |
πd³/6 |
| Circumference C | C/(2π) |
C/π |
C |
C²/π |
C³/(6π²) |
| Surface area A | √(A/(4π)) |
√(A/π) |
√(Aπ) |
A |
A^(3/2)/(6√π) |
| Volume V | ³√(3V/(4π)) |
2³√(3V/(4π)) |
2π × ³√(3V/(4π)) |
4π(³√(3V/(4π)))² |
V |
Common pitfalls: mixing units between inputs, entering negative values, or rounding too early. If the consistency check warns you, double-check your unit labels and π choice.
With r = 5 cm, d = 10 cm, A = 100π cm² ≈ 314.16 cm², and V = 500π/3 cm³ ≈ 523.60 cm³.
With d = 10 cm, the radius is 5 cm, so the volume is also 500π/3 cm³ ≈ 523.60 cm³.
A = 4π × 7² = 196π, so the surface area is approximately 615.75 square units.
If V = 288π cm³, then r = ³√(3V/(4π)) = 6 cm.
Double the radius and S grows by 4× while V jumps by 8×. Radius changes dominate volume because of the r³ term.
Airplanes fly “curved” great-circle routes because those are the shortest paths on a sphere—straight on a globe, bendy on a flat map.
You can’t flatten a sphere without stretching or cutting (Gauss’s Theorema Egregium). Every world map picks what to distort—area, shape, or distance.
Outside a uniform sphere, gravity acts as if all mass is at its center. That’s why planet-sized bodies pull like perfect point masses in orbital math.
Earth’s equatorial radius is ~21 km larger than its polar radius. The “oblate spheroid” bulge comes from rotation; perfect spheres are rare in nature.
You can solve from radius, diameter, circumference, surface area, or volume. The advanced check also lets you enter more than one value to compare consistency.
Divide the diameter by 2 to get the radius, then use V = (4/3)πr³. Equivalently, V = πd³/6.
Rearrange V = (4/3)πr³ to r = ³√(3V/(4π)). Enter volume as the known value and the calculator performs this step.
First find r = ³√(3V/(4π)), then calculate A = 4πr². The calculator shows both the substitution and the final surface area.
In geometry, a sphere is the set of points on the outer surface at a fixed distance from the center. A ball usually means the solid region inside that surface as well.
A sphere has many circular cross-sections. The value reported here is the great-circle circumference, C = 2πr = πd, around the widest circle.
Surface area covers the outside skin of the sphere, so it uses square units such as cm². Volume measures enclosed space, so it uses cubic units such as cm³.
Yes. Computation is entirely client-side; nothing is uploaded.
Yes. Choose separate labels for length, area, and volume units, set decimal places, and select the π precision your class or project requires.